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hand side vanishes mg kv2 ∞ = 0 corresponds to a stable equilibrium. In fact for some realistic values of the parameters the ode becomes dv dt = 9:8 9:8 10−4v2; v(0) = 0 which can be solved using separation of variables: dv 1002 v2 = 9:8 10−4dt and partial fractions 1 200 (dv 100 v + dv 100+ v) = 9:8 10−4dt If we integrate this we get 1 .

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